# Vocabulary/scapco

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`[x] u S: n y`Spread Conjunction

Rank Infinity *-- operates on [x and] y as a whole --*
WHY IS THIS IMPORTANT?

`(u S:0 y)` applies verb `u` to each leaf of `y`, creating an array
whose items are the results of the leaves, with framing fill added as needed.

Contrast this with Level At (`u L:0 y`), which returns a result in which each leaf of `y` has been **replaced** by the result of executing `u` on it.

A leaf of `y` is a noun inside `y` that itself has no boxed contents.

A leaf is either empty or unboxed.

] y=: (<0 1),(<<2 3),(<<<4 5) +---+-----+-------+ |0 1|+---+|+-----+| | ||2 3|||+---+|| | |+---+|||4 5||| | | ||+---+|| | | |+-----+| +---+-----+-------+ NB. y is sample noun of nested boxed items NB. --The leaves are (0 1), (2 3) and (4 5) u=: |. NB. sample verb (Reverse) to apply to leaves u S:0 y 1 0 3 2 5 4

Compare this with the action of Level At (`L:`)

`([x] u S:n y)` applies `u` to the leaves of `y` in the same way as `([x] u L:n y)`
but it collects the results as the items of an array.

See Level At (`L:`) for details, including

- values of
`n`other than`0` - negative values of
`n` - the dyadic case
`(x S: n y)`

### Common Uses

Apply verb `u` to the leaves (innermost opened items) of a boxed noun `y`

] y=: 'alpha' ; 'bravo' ;'charlie' +-----+-----+-------+ |alpha|bravo|charlie| +-----+-----+-------+ toupper S:0 y ALPHA BRAVO CHARLIE

### Related Primitives

Level Of (`L. y`),
Level At (`u L: n`)